Question

For the function f(x) = -2(x + 3)^2 -1, identify the vertex, domain, and range. A.) The vertex is (3, -1), the domain is all real numbers, and the range is y ≥ -1. B.) The vertex is (3, -1), the domain is all real numbers, and the range is y ≤ -1. C.) The vertex is (-3, -1), the domain is all real numbers, and the range is y ≤ -1. D.) The vertex is (-3, -1), the domain is all real numbers, and the range is y ≥ -1

Answer 1

ok so domain is all allowed numbers look at deonomenator and don't allow any numbers that will make it zero none that means domain=all real numbers vertex in form y=a(x-h)^2+k (h,k)=vertex we have y=-2(x+3)^2-1 h=-3 k=-1 vertex=(-3,-1) range the vertex opens down so max is y=-1 y≤-1 domain is all real vertex is (-3,-1) y≤-1 C