Question

Find 3 consecutive integers if the sum of the 2nd and 3d integers is -17.

Answer 1

we can write three consecutive integers like this:

`n,n+1,n+2`

we have that the sum of the 2nd and the 3rd integers is -17, then:

`(n+1)+(n+2)=-17`

solving for n, we get the following:

`\begin{gathered} (n+1)+(n+2)=-17 \\ \Rightarrow n+n+1+2=-17 \\ \Rightarrow2n+3=-17 \\ \Rightarrow2n=-17-3=-20 \\ \Rightarrow n=(-20)/(2)=-10 \\ n=-10 \end{gathered}`

therefore, the three consecutive integers are -10, -9 and -8