77 ¹¹/₃₂ in²
The area that he can cover with these tiles is 77 ¹¹/₃₂ in²
Further explanation
To solve the above questions, we need to
recall some of the formulas as follows:
Area of Square = (Length of Side)²
Perimeter of Square = 4 × (Length of Side)
Area of Rectangle = Length × Width
Perimeter of Rectangle = 2 × ( Length + Width )
Area of Rhombus = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Rhombus = 4 × ( Length of Side )
Area of Kite = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Kite = 2 × ( Length of Side₁ + Length of Side₂ )
Let us now tackle the problem !
Given:
Number of Tiles = N = 9 tiles
Length of Tiles = L = 3¹/₈ inches
WIdth of Tiles = W = 2³/₄ inches
Unknown:
Total Area = A = ?
Solution:
Area of One Tile.
Area of Rectangle=Length×WidthArea of Rectangle=Length×Width
Area of Rectangle=318×234Area of Rectangle=381×243
Area of Rectangle=81932 in2Area of Rectangle=83219 in2
Total Area.
Total Area=Number of Tiles×Area of One TileTotal Area=Number of Tiles×Area of One Tile
Total Area=9×81932Total Area=9×83219
Total Area=771132 in2Total Area=773211 in2
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