Question

I need the answer to question I have enclosed below

Answer 1

`x=\pm8i`

Step-by-step explanation

We want to solve the equation:

`2x^2+128=0`

This can be solved using the square root method.

To do this, first, separate the terms in the equation:

`2x^2=-128`

Next, divide both sides by 2:

`\begin{gathered} x^2=-(128)/(2) \\ x^2=-64 \end{gathered}`

Then, find the square root of both sides of the equation:

`\begin{gathered} \sqrt[]{x^2}=\sqrt[]{-64} \\ x=\sqrt[]{64\cdot-1}=\sqrt[]{64}\cdot\sqrt[]{-1} \\ x=\pm8\cdot i \\ x=\pm8i \end{gathered}`

That is the solution to the equation.