Question

Perform the indicated operation.

(6f^2 - 13 - 11f) ÷ (3f - 4)

Answer 1

2f - 1
3f - 4|6f² - 11f - 13
- (6f² - 8f)
-3f - 13
- (-3f - 3)
-10


`It\ is\ equal\ to\ 2f - 1 + (-10)/(3f - 4).`

Answer 2

`2f - 1 +(-10)/(3f-4)`

Explanation:

Given :-
`(6f^(2)-13-11f)/(3f-4)`

We perform this operation by long division method which is shown in figure-1

steps as follows:

1) we multiply 3f-4 by 2f and get 6f² -8 and then

2) subtract 6f² -8 from 6f² - 13 -11f ,we we get -3f - 13

3) now multiply 3f-4 by -1 and get -3f - 13

4) subtract -3f -3 from -3f -13 ,we we get -10

where dividend is 6f² - 13 -11f, divisor is 3f-4, Quotient is 2f - 1 and remainder is -10.

`2f - 1 +(-10)/(3f-4)`