Question

Write an equation of a line that passes through the point (2,0) and is perpendicular to the line y=−12x+3.

Answer 1

Equation of a line that passes through the point (2,0) and is perpendicular to the line y=−12x+3 is

`y = 2x-4`

Explanation:

Slope of the line y=−12x+3 is m1=-12

We know slopes of perpendicular lines are negative reciprocals of each other. Therefore m2=2

Equation of line in point slope form is

`y-y_1 = m_2 (x-x_1)` ----------- (1)

Here

`m_2 = 2 \ \ \ and \ \ \ (x_1, y_1) = (2, 0)`

Substituting values in equation (1)

`y-0 = 2 (x-2)`

`y = 2x-4`