Find four consecutive multiples of 5 whose sum is 90

Question

asked Sep 28, 2015 106k views

1 Answer

Bernzkie · Answer 1 · 2015-10-04T11:49:45+0000

M₅+(M₅+5)+(M₅+10)+(M₅+15)=90

5M₅+ 30=90

5M₅=90-30

5M₅=60

M₅=60:5

M₅=12

M₅+5=12+5=17

M₅+10=12+10=22

M₅+15=12+15=27