Question

Solve y - 1 = 4y/3 - 2/3

Answer 1

`y-1 = (4y)/(3) - (2)/(3)`

Multiply both sides by 3 :


`y*3-1*3= (4)/(3) *3 - (2)/(3) *3`


`3y-3=4y-2`

Add 3 to both sides:


`3y - 3 + 3 = 4 y -2 + 3`


`3y = 4y+1`

Subtract 4 y from both sides:


`3y-4y = 4y+1-4y`


`-y = 1`

Divide both sides by -1 :


`(-y)/(-1) = (1)/(-1)`


`y = -1`

hope this helps!