Question

b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?​

Answer 1

Twice.

Step-by-step explanation:

The momentum of an object is given by :

p = mv

Where

m is mass and v is the velocity

If the mass of the ball were doubled, m'=2m and v'=v=3 m/s

New momentum,

p'=m'v'

p'=2m × v

p'=2mv

or

p'=2p

So, the new momentum becomes twice the initial momentum.