Question

What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?

Answer 1

Solutions

1) Simplify 4z−3−1 to 4z−4

2(4z−4)=166−46

2) Simplify 166−46 to 120

2(4z−4)=120

3) Divide the equation from both sides by 2

4z−4=120 ÷ 2

4) Simplify 120 ÷ 2 to 60

4z−4=60

5) Add 4 to both sides

4z=60+4

6) Simplify 60+4 to 64

4z=64

7) Divide both sides by 4z=64 ÷ 4

8) Simplify 64 ÷ 4 to 16

z=16

Answer 2

Refine
`2(4z-3-1)`


`= 2(4z-4)`

Refine :
`166 - 16 = 120`

therefore:


`2(z-4) = 120`

Divide both sides by 2 :


`(2(z-4))/(2) = (120)/(2)`


`4z-4 = 60`

add 4 to both sides:


`4z-4+4 = 60+4`


`4z = 64`

Divide both sides by 4 :


`(4z)/(4) = (64)/(4)`


`z = 16`

hope this helps!