Question

I attach my worksheet Suppose that a random variable X can take on integer values from 0 to 5 and its pdf is defined as follow p(x)=11-2x/36calculate p(x) for all possible values

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

x = 0 to 5

p(x) = (11 - 2x) / 36

Step 02:

calculate p(x):

integer values:

x = 0:

`p(0)=\frac{11-2(0)_{}}{36}=(11)/(36)`

x = 1:

`p(1)=(11-2(1))/(36)=(9)/(36)=(1)/(4)`

x = 2:

`p(2)\text{ = }(11-2(2))/(36)=(11-4)/(36)=(7)/(36)`

x = 3:

`p(3)\text{ = }(11-2(3))/(36)=(11-6)/(36)=(5)/(36)`

x = 4:

`p(4)\text{ = }(11-2(4))/(36)=(11-8)/(36)=(3)/(36)=(1)/(12)`

x = 5:

`p(5)\text{ = }(11-2(5))/(36)=(11-10)/(36)=(1)/(36)`

That is the full solution.