Question

if the solubility of a gas is 7.5 g/L at 404 pressure, what is the solubility of the gas when the pressure is 202 kPa?

Answer 1

Hello!

Data:

C1 (initial concentration) = 7.5 g/L

P1 (initial pressure) = 404 kPa

C2 (final concentration) = ? (g/L)

P2 (final pressure) = 202 kPa

We apply the data to the formula of the solubility of gases in a liquid (Henry's Law), let us see:

`\boxed{ (C_1)/(P_1) = (C_2)/(P_2)}`

Solving:

`(7.5)/(404) = (C_2)/(202)`

`404*C_2 = 7.5*202`

`404C_2 = 1515`

`C_2 = (1515)/(404)`

`\boxed{\boxed{C_2 = 3,75\:g/L}}\end{array}}\qquad\checkmark`

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I Hope this helps, greetings ... Dexteright02!

Answer 2

henry's law :

S₁ / P₁ = x / P₂

7.5 / 404 = x / 202

x = 7.5 * 202 / 404

x = 1515 / 404

x = 3.75 g/L

hope this helps!