Question

Solve the following complex equation:16 + 12i = 4x - 6yiA. X = 2 & y = - 4B. X = -2 & y = 4C. x = 4 & y = -2D. x = - 4 & y = 2

Answer 1

For these two complex numbers to be the same, we need to equal the real part and the complex part as follows:

16 = 4x [1]

12 = -6y [2]

Then

Solving for x in [1]

x = 4

Solving for y in [2]

y = -2

Therefore, the answer is x = 4, and y = -2 (Option C).