Question

A jet engine develops 1.0 x 10 N of thrust to move an airplane forward

at a speed of 9.0 x 10 km/h. What
is the power output of the engine?

Answer 1

So P = 1.0x10^5N*(900km/h*1000m/km*1h/3600s) = 2.5x10&6W = 25 MW ans c

Answer 2

Power,
`P=25* 10^6\ W`

Step-by-step explanation:

Given that :

Force applied to the engine,
`F=1* 10^5\ N`

Speed of the engine,
`v=9* 10^2\ km/h=250\ m/s`

To find :

The power output of the engine

Solve :

Power output of the engine is given by :

`P=(W)/(t)`

W is the work done

t is the time taken

Also,
`W=F* d` and
`v=(d)/(t)`

`P=(F* d)/(t)`

`P=F* v`

`P=1* 10^5\ N* 250\ m/s`

`P=25* 10^6\ W`

So, the power output of the engine is
`25* 10^6\ W`.