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Two cities are 210 km apart. A train traveled this distance in 4 2/3 hours and then made the return trip at a speed of 50 2/5 km/h. How many times greater (or less) was the train’s speed on the return trip?

User Emertechie
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1 Answer

4 votes

4 (2)/(3)= (14)/(3)

So,
(210km)/( (14)/(3)hr )= 45km/h


50 (2)/(5) = (252)/(5)


So,
(252)/(5)/45= 1.12 times greater on the return trip.

User Don Pflaster
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7.4k points