Question

c.Mark had car trouble 120 mi from home and drove toward home at 30 mph. Hisroommate left home and drove to meet him at 50 mph. How long did it take for them tomeet?

Answer 1

Given data:

The given distance is d=120 mi.

The given speed of Mark is s=30 mph.

The given speed of Mark's friend is s'=50 mph.

The expression for the distance covered by Mark when he meet with his friend at any time t is,

`x=30t`

The expression for the distance covered by Mark's friend when he meet with Mark at any time t is,

`120-x=50t`

Substitute 30t for x in the above expression.

`\begin{gathered} 120-30t=50t \\ 120=80t \\ t=1.5\text{ h} \end{gathered}`

Thus, after 1.5 hours they meet.