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Exercise N° 62 :The next reaction is at equilibrium.4HCl (g) + O2 (f) <=> 2H2O (g) + 2Cl2 (g)∆H ° = -114.4KjDescribe 4 modifications that can be made to the mixture to increase the amount of Cl2 (g) to balance.

User DomQ
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Answer:

Step-by-step explanation:

Here, we want to get the modifications that could be made to the mixture to increase the amount of chlorine gas

We can see that the chlorine gas is one of the products here. So the question is basically asking what can be done to the reactant mixture so as to get more of a specific product.

a)i) Increase in the number of moles of HCl

This is one of the reactants. By ensuring that we have more of this specific reactant, it will give rise for more reactant molecule to be supplied and that helps to bring more product

ii) Increase in the number of moles of O2

This ensures that more O2 molecules are supplied. This ensures that we have more of the reactant and that gives us more product

b) Increase in Pressure in the forward reaction

As we can see from the reaction equation, there is a decrease in volume. We have 5 moles of reactants and 4 moles of products. This shows a decrease in volume. By increasing the pressure in the reactant chamber, more of the products will be obtained

c) Decrease in Temperature

From the reaction's enthalpy change, we can see that the reaction is exothermic since it is negative. What this mean is that heat is a product of the reaction. By increasing the temperature, the equilibrium position shifts to the left. But by decreasing the temperature, we have more product formed as the equilibrium shifts to the right

d) Removal of Products as they are formed

When the products are removed from the chamber as at when formed, it gives more space for reactants to combine and that helps to get even more amount of products. This is decongesting the product side of the reactants chamber

User Minikomi
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