Tony's architecture firm is constructing a square pyramid play structure for a school. will be 9 feet, and each face is a triangle with a height of 8 feet. The pyramid will be covered. What will be the amount of building material needed to cover the pyramid? 0 144 square feet 225 square feet 0 288 square feet 0 369 square feet
we know that
The surface area of the square pyramid is equal to the area of its square base plus the area of its four triangular faces
so
Find out the surface area
the length side of the square is 9 ft
SA=(9)(9)+4[(1/2)(9)(8)]
SA=81+144
SA=225 ft^2
therefore
the answer is 225 square feet