Question

Warrick and Charlie are recording their distance from the ground t in seconds after jumping from a trampoline. The table below shows the time, t, in seconds and Warricks distance, W(t), in meters t seconds after jumping from the trampoline. The function C(t)= -t^2+4t+5 models Charlie’s distance C(t) in meters t seconds after jumping from the trampoline ( table is in the photo)

Answer 1

`\begin{gathered} C\mleft(t\mright)=-t^2+4t+5 \\ =-(t^2-4t-5) \\ =-(t-5)(t+1) \\ C(t)=(t+1)(-t+5) \\ \\ \text{ that means that if } \\ -10} \\ \\ \text{ Charlie stayed in the air by 6 seconds, while Warrick stayed 3.5 seconds, that means } \\ \text{Charlea stayed in the air longer} \end{gathered}`