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4 votes
Can someone please explain how to solve these two math equations?

2x^2-3x-35=0

56z^2+2=22z

User Noctilux
by
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1 Answer

4 votes
#1.

Question: 2x^2 − 3x − 35 = 0

Step 1: Factor left side of equation): (2x + 7) (x − 5) = 0
Step 2: Set factors equal to 0.): 2x + 7 = 0 or x − 5 = 0

ANSWER: x = −7/2 or x = 5
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#2.

Question: 56z^2 + 2 = 22z

Step 1: Subtract 22z from both sides.):

56z^2 + 222z = 22z 22z
56z^2 22z + 2 = 0
Step 2: Factor left side of equation.):


2(7z − 1)(4z − 1) = 0

Step 3: Set factors equal to 0.):


7z − 1 = 0 or 4z − 1 = 0

ANSWER:
z = 1/7 or z = 1/4
User MarioH
by
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