Question

I would like to be help with number 47 please

Answer 1

Explanations:

The formula for calculating the percent impurity of oxygen is expressed as:

`\%O=\frac{mass\text{ of oxygen}}{Mass\text{ of water}}*100`

Given the following parameter

Mass of water = 36.8 grams

Determine the moles of water

According to the ideal gas equation, PV = nRT

`\begin{gathered} n=(PV)/(RT) \\ n=(1atm*64L)/(0.08205*273K) \\ n=(64)/(22.399) \\ n=2.857moles \end{gathered}`

Determine the mass of oxygen

Mass of O2 = moles * molar mass

Mass of O2 = 2.857 * 16

Mass of O2 =