Question

A line contains (4,2) and (0,1) what is the equation of the line

Answer 1

When you need the equation of a line, you need to find the slope (m) and the y-intercept (b). the slope is fairly easy to find, we simply find the second y- the first y divided by the difference of the second x and the first x. this will look like
(1-2)/(0-4)= 1/4. that is our slope. next we need to find the y-intercept, that is when x=0. for this problem we are actually given it with the second point (0,1) that means our y-intercept is 1. now we have the everything we need for the equation y=mx+b. we know that m=1/4 and b=1, so we can plug that in and get y=1/4x+1

Answer 2

First we need to find the slope of the line.


`Slope = (y_2-y_1)/(x_2-x_1) = (2 - 1)/(4-0) = (1)/(4)`

Our equation of the line will be in the form of y = mx + b, where m is the slope and b is the y-intercept.

We have found the slope. All we need to find is the y-intercept. Luckily, they gave us the y-intercept!

The y-intercept can be found when x = 0. And one point they gave us is (0,1). That means the y-intercept is 1.

The equation of the line is


`y = (1)/(4)x + 1`