A line contains the point (8, –5). If the slope of the line is 5/7, write the equation of the line using point-slope form.

Question

asked Nov 11, 2017 10.5k views

2 Answers

Manu Mathew · Answer 1 · 2017-11-12T20:15:28+0000

Answer: The required equation of the line is

Step-by-step explanation: Given that a line contains the point (8, -5) and the slope of the line is {tex]\dfrac{5}{7}.[/tex]

We are to write the equation of the line using point-slope form.

We know that

the equation of a line with slope m and passing through the point (a, b) is given by

For the given line, we have

m=(5)/(7),~~~(a,b)=(8,-5).

Therefore, the equation of the line will be

$y-b=m(x-a)\\\\\Rightarrow y-(-5)=(5)/(7)(x-8)\\\\\Rightarrow y+5=(5)/(7)(x-8).$

Thus, the required equation of the line is

Amada · Answer 2 · 2017-11-17T08:15:16+0000

Answer:

Explanation:

The point slope form of a line having slope m and point (a,b) is given by :-

(y-b)=m(x-a)

Given: A line contains the point = (8, –5)

The slope of the line =
(5)/(7)

Now, the point slope form of a line having slope
and point (8,-5) is given by :-

$(y-(-5))=(5)/(7)(x-8)\\\\\Rightarrow\ (y+5)=(5)/(7)(x-8)$

Hence, the equation of the line =