Question

Assuming a 25% efficiency, how many Calories would a horse need to consume to work at 1.0 hp for 2.0 hh ?

Answer 1

E = 7.11 ×
`10^(-7)` Cal

Step-by-step explanation:

given data

efficiency = 25 %

solution

first we get here E by the power that is express as

p =
`(E)/(t)` ...........1

E = p × t

E = 1 × 2 ×
`(1hp)/(746w) * (1hr)/(3600 s)`

E = 7.447 ×
`10^(-7)` J

and

Ein is get by efficiency

Ein =
`(Eout)/(\eta )` ..................2

Ein =
`(7.447 * 10^(-7))/(.25 )`

Ein = 29.788 ×
`10^(-7)` J

so required energy is

E = 29.788 ×
`10^(-7)` ×
`(1Cal)/(4.184J)`

E = 7.11 ×
`10^(-7)` Cal