Question

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Independent practice
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Find the area of each figure. Round to the nearest tenth if
necessary.
(Example
(02 cm
12 cm
6 yd
4.5 cm
16 yd
8 yd
2 cm
show) 24 yd
5 cm
1 m.
15 c
15 m

Answer 1

1. 64 cm²

2. 240 yard²

3. 85.13 cm²

4. 193.36 m²

Explanation:

Ques 1: We are given two rectangle with dimensions,

Length = 12 cm, Width = 4.5 cm and Length = 5 cm, Width = 2 cm.

As, we know, Area of a rectangle = Length × Width

So, we have,

Area of 1st rectangle = 12 × 4.5 = 54 cm²

Area of 2nd rectangle = 5 × 2 = 10 cm²

Thus, the total area of the figure = 54 + 10 = 64 cm²

Ques 2: We are given a triangle and a rectangle with dimensions,

Triangle: Base = 24-12 = 12 yd and Height = 8 yd

As, Area of a triangle =
`(1)/(2) (Base * Height)`

i.e. Area of the triangle =
`(1)/(2) (12* 8)`

i.e. Area of the triangle =
`(1)/(2)* 96`

i.e. Area of the triangle = 48 yard²

Rectangle: Length = 24 yd, Width = 8 yd

As, we know, Area of a rectangle = Length × Width

i.e. Area of a rectangle = 24 × 8 = 192 yard²

So, the total area of the figure = 48 + 192 = 240 yard².

Ques 3: We are given a triangle and a semi-circle with dimensions,

Triangle: Base = 8 cm and Height = 15 cm

As, Area of a triangle =
`(1)/(2) (Base * Height)`

i.e. Area of the triangle =
`(1)/(2) (8* 15)`

i.e. Area of the triangle =
`(1)/(2)* 120`

i.e. Area of the triangle = 60 cm²

Semi-circle: Diameter = 8 cm implies Radius = 4 cm.

So, Area of the semi-circle =
`(\pi r^(2))/(2)`

i.e. Area of the semi-circle =
`(\pi 4^(2))/(2)`

i.e. Area of the semi-circle =
`(16\pi)/(2)`

i.e. Area of the semi-circle =
`(50.26)/(2)`

i.e. Area of the semi-circle = 25.13 cm²

Thus, the total area of the figure = 60 + 25.13 = 85.13 cm²

Ques 4: We are given a rectangle and a semi-circle of dimensions,

Rectangle: Length = 15 m, Width = 7 m.

As, we know, Area of a rectangle = Length × Width

i.e. Area of a rectangle = 15 × 7 = 105 m²

Semi-circle: Diameter = 15 m implies Radius =
`(15)/(2)` = 7.5 m

So, Area of the semi-circle =
`(\pi r^(2))/(2)`

i.e. Area of the semi-circle =
`(\pi (7.5)^(2))/(2)`

i.e. Area of the semi-circle =
`(176.72)/(2)`

i.e. Area of the semi-circle = 88.36 m²

Thus, the total area of the figure = 105 + 88.36 = 193.36 m²