Question

How many grams of KNO₃ should be used to prepare 2.00L of a .500 M solution ?

Answer 1

Volume = 2.00 L

Molarity = 0.500 M

M = n / V

0.500 = n / 2.00

n = 0.500 * 2.00

n = 1.0 mole KNO₃

Molar mass KNO₃ = 101.1032 g/mol

1 mole ------ 101.1032 g
1.0 mole ------ ?

mass = 1.0 * 101.1032 g / 1

mass = 101.1032 g of KNO₃

hope this helps!