Question

Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

Answer 1

M₁ *V₁ = M₂ * V₂

12.0 * V₁ = 6.0 * 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

hope this helps!

Answer 2

Answer : The volume of concentrated hydrochloric acid is, 0.25 liters

Explanation :

Using neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L

`M_2` = molarity of hydrochloric acid = 6 M = 6 mole/L

`V_1` = volume of concentrated hydrochloric acid = ?

`V_2` = volume of hydrochloric acid = 500 ml = 0.5 L

Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.

`12mole/L* V_2=6mole/L* 0.5L`

`V_2=0.25L`

Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters