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P and S waves from an earthquake travel at different speeds and this difference helps in locating the epicenter (point of origin) of the earthquake. (a) Assuming P waves travel at 10.3 km/s and S waves travel at 4.2 km/s, how far away did the earthquake occur if a particular seismic station detects the arrival of these two types of waves 3.25 minutes apart

User Tharris
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1 Answer

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Answer:

x = 1382.9 km

Step-by-step explanation:

The speed of the wave is constant, so we can use the uniform motion relationships

p wave


v_p = x / t₁

t₁ = x /v_p

S wave

v_s = x / t₂

t₂ = x / v_s

indicate that the time difference between the two waves is

t₂ - t₁ = 3.25 min (60 s / 1 min)

t₂ -t₁ = 195 s

let's substitute


(x)/(v_s) - (x)/(v_p) = 195

x (
(1)/(v_s) - (1)/(v_p) = 195

let's calculate

x
( (1)/(4.2) - (1)/(10.3) ) = 195

x (0.1410) = 195

x = 195 /0.141

x = 1382.9 km

User Bishnu Rawal
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