Question

I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem is attached. I got 6.425 for the other side of the triangle for reference if that helps.

Answer 1

So,

Remember that the cosine function is a relation between the adjacent side of the angle given and the hypotenuse of the triangle.

Then we could draw:

We're asked to find tanA, which is the relation between the opposite side of angle A and its adjacent side.

For this, we should find the value of x using the pythagorean theorem first:

`\begin{gathered} x=\sqrt[]{8^2-5^2} \\ x=\sqrt[]{64-25} \\ x=\sqrt[]{39} \end{gathered}`

Now, tanA will be:

`\tan A=\frac{\sqrt[]{39}}{5}`