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A ball is thrown at an angle of 30° off the horizontal, with an initialvelocity of 28 m/s. What is the maximum height the ball will reach?

User Marco Papula
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1 Answer

15 votes
15 votes

sen(30)\ast28=(14m)/(s)
\begin{gathered} v^2=(14m/s)^2-2ad \\ (14^2)/(2\ast9.81)=d=9.99m \end{gathered}

A ball is thrown at an angle of 30° off the horizontal, with an initialvelocity of-example-1
User JGK
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