Question

Through: (3-2), Perpendicular to y = 3×+ 3

Answer 1

if the line is perpendicular to:

`y=3x+3`

then we know that the slope will be the negative reciproc of 3 so:

`m=-(1)/(3)`

Now we use this equation to find the intercept in the y axis:

`m=(y-y_1)/(x-x_1)`

we replace the slope, the coordinate (3,-2) and x=0 so:

`\begin{gathered} -(1)/(3)=(y-(-2))/(0-3) \\ (3)/(3)=y+2 \\ 1-2=y \\ -1=y \end{gathered}`

So the final equation will be:

`y=-(1)/(3)x-1`