Question

Solve the equation below for y1/2 (y - 8) = 1/4y - 2

Answer 1

`\begin{gathered} (1)/(2)(y-8)=(1)/(4)y-2 \\ (y)/(2)-(8)/(2)=(1)/(4)y-2 \\ collec\text{t like terms} \\ (1)/(2)y-(1)/(4)y=-2+4 \\ (2y-y)/(4)=2 \\ \text{cross multiply} \\ y=8 \end{gathered}`