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What are the values of x in the equation x(x-6)=4(x+6)

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x la patrat - 6x = 4x+24<=>x la a doua -10x-24=0
D= 100-4×1(-24)
D=100+96
D=196
X1,2= 10 plus minus 14 : 2 <=>X1=10-14:2=-2 and X2= 10+14:2= 2
User Mahesh Giri
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x(x-6)=4(x+6)

Multiply out:

x² - 6x = 4x + 24

x² - 6x - 4x - 24 = 0

x² - 10x - 24 = 0

This is a quadratic equation


x² - 10x - 24 = 0 Divide through by 2

Multiply first and last coefficients: 1*-24 = -24

We look for two numbers that multiply to give -24, and add to give -10

Those two numbers are -12 and 2.

Check: -12*2 = -24 2 + -12 = -10

We replace the middle term of -10x in the quadratic expression with 2x -12x


x² - 10x - 24 = 0

x² + 2x - 12x - 24 = 0

x(x + 2) - 12(x + 2) = 0

(x + 2)(x - 12) = 0

x + 2 = 0 or x - 12 = 0

x = 0 -2 x = 0 + 12

x = -2 x = 12

The solutions are x = -2 or 12
User Ductran
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