Question

Could you help me out

Answer 1

we must use trigonometric ratios to solve the right triangle

i will use the cosine

`\begin{gathered} \cos (\alpha)=(A)/(H) \\ \end{gathered}`

where alpha is the angle, a the adjacent side and H the hipotenuse,

so replacing

`\cos (73)=(6)/(x)`

now solve for x

`\begin{gathered} x=(6)/(\cos (73)) \\ \\ x=20.52 \end{gathered}`

so the right option is I