Question

Find two consecutive whole numbers that 21 lies between.Ú 1 and|Х5?

Answer 1

Answer:

The consecutive numbers are 4 and 5

Step-by-step explanation:

We need to find square root of two whole numbers a and b, such that

`\sqrt[]{a}<√(21)<\sqrt[]{b}`

For

`\sqrt[]{a},\sqrt[]{b}`

to be whole numbers, then a and b must be perfect squares.

The perfect squares that satisfy this condition are:

16 and 25, therefore,

`\begin{gathered} \sqrt[]{16}<\sqrt[]{21}<\sqrt[]{25} \\ \\ 4<\sqrt[]{21}<5 \end{gathered}`

The numbers are 4 and 5