Question

In a batch of 960 calculators, 8 were found to be defective. What is a probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.

Answer 1

out of 960 calculators, 8 were found be to defective

Probability:

`(8)/(960)`
0.00833...
As a Percent:
0.00833....× 100
0.833%
To the nearest tenth of percentage:
0.833% ≈ 0.8%

Answer 2

0.8% is a probability that a calculator chosen at random will be defective

Explanation:

Probability of any event is given by:

`P(A) = \frac{\text{Number of required outcomes}}{\text{Total number of possible outcomes}}` where, A is any event.

As per the statement:

In a batch of 960 calculators, 8 were found to be defective.

here,

A = Defective calculator.

⇒Number of defective calculator = 8

and

Total number of outcomes = 960 calculators.

then by definition we have;

`P(A) = (8)/(960)`

Simplify:

`P(A) \approx 0.00833333333` = 0.833333333 %

Therefore, a probability that a calculator chosen at random will be defective to the nearest tenth place is, 0.8 %