Question

45 - 45°-90° YOU TRY! Solve for x and y: B + 45° y 45° av2 X a 45° 45° NIS 2 С a

Answer 1

When we have a right triangle like the one we have in the image, we can use the relationships between the legs and the hypotenuse.

The relationships are given by,

`\sin 45=(x)/(y),\text{ }\cos 45=\frac{\frac{\sqrt[]{2}}{2}}{y}`

We need to find x, however, to find x we must find y first,

We solve for y,

`\begin{gathered} y=\frac{\frac{\sqrt[]{2}}{2}}{\cos 45} \\ y=1 \end{gathered}`

Now that we have the value of y, we can find x,

`\begin{gathered} x=\sin 45* y \\ x=\sin 45*1 \\ x=\frac{\sqrt[]{2}}{2} \end{gathered}`