Question

Can anybody help me out with this?

Answer 1

• 1) 17 ft, 2) 12π yd, 3) 3 in, 4) 3.19π in, 5) 9π

Explanation:

Q1

AT = 8.5 ft

AT is radius, the diameter is:

• d = 2AT = 2*8.5 ft = 17 ft

Q2

AH = 6 yd, AH is radius

• C = 2πr = 2π*6 = 12π yd

Q3

• C = 6π in
• 2πr = 6π
• r = 6 π/2π = 3 in

Q4

∠MAT = 115°

Arc MT is:

• 2πr*115/360° =
• 2π*5*0.319 =
• 3.19π in

Q5

C = 6π, A = ?

• 2πr = 6π
• r = 3

A = πr² = π*3² = 9π