Write a balanced ionic equation for the dissociation of KOH

SoGoddamnUgly asked May 23, 2023

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SoGoddamnUgly asked May 23, 2023

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Answer

The balanced ionic equation for the dissociation of aqueous KOH is:

KOH(aq) ⇄ K⁺(aq) + OH⁻(aq)

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