Question

Can you solve (4x-3)/(x+2)+(15)/(x-3)

Answer 1

`(4x-3)/(x+2)` +
`(15)/(x-3)` = 0
1st step: We need to have a common denominator.
So we do this:

`((4x-3)*(x-3))/((x+2)*(x-3))` +
`((15)*(x+2))/((x-3)*(x+2))` = 0
2nd step: Distribute them

`(4x^(2)-3x-12x+9)/((x-3)(x+2))` +
`(15x+30)/((x+2)(x-3))` = 0
3rd step: Do the rest of the equation!
We can put it on one fraction, its fine.

`(4x^2-15x+9+15x+30)/((x+2)(x-3))` = 0

`(4x^2+39)/((x+2)(x-3))` = 0 (-15 and 15 cancels out)
4th step: take the denominator to the other side
4x²+39 = 0 (anything × 0 = 0)
5th step: Take 39 to the other side
4x² = -39
6th step: Divide by 4 on both sides

`(4x^2)/(4)` =
`-(39)/(4)`
(4 and 4 cancels out)
x² =
`-(39)/(4)`
7th step: Take the square root to keep x alone
x =
`-\sqrt(39)/(4)`
It can also be written as:
x =
`-( √(39) )/( √(4) )`
Final answer:
x =
`-( √(39) )/(2)`

Answer 2

Please see the pic, I'd solved in it.