Question

Which expression represents the factored form of 6x^2 - 13x - 5?

a) (2x + 5) (3x - 1)
b) (2x- 5) (3x + 1)
c) (6x-5) (x + 1)
d) 6x + 1) (x - 5)

Answer 1

to FL and add
multiply first terms and multiply last terms and add and see if we get the middle term
example
(x+2)(2x-3)=2x^2+x-6x
2*2x+x*-3=4x-3x=x=middle term so



a. (2x+5)(3x-1)
2x*-1+5*3x=-2x+15x=13x, no we want -13x

b. (2x-5)(3x+1)
2x*1+-5*3x=2x-15x=-13x correct



answer is B

Answer 2

For the quadratic trinomial
`ax^2+bx+c` the following formula

`ax^2+bx+c=a(x-x_1)(x-x_2)`, where
`x_1, x_2` are trinomial roots, holds.

1. For trinomial
`6x^2 - 13x - 5` find the roots:

`image`.

2. The factoring form is

`6x^2-13x-5=6\left(x+(1)/(3)\right)\left(x-(5)/(2)\right) =(3x+1)(2x-5)`

Answer: correct option is B.