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the pressure of a sample of gas was 97.8 kPa and the volume of the gas was 3.75 l. if the gas occupied a container with a volume of 8.00 L, what would the pressure in the container be?

User Jcr
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1 Answer

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If the temperature stays the same then:
P1V1=P2V2
so:
97.8*3.75=8P
366.75=8P
P= 45.84 kPa is the new pressure
User Angad Bansode
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