Question

Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A graduated cylinder contains 31.0 g of heptane and 37.0 g of water. 1st attemptWhat is the volume of heptane in the cylinder? What is the volume of water in the cylinder?What is the total volume of liquid in the cylinder?

Answer 1

Given that the density of heptane is

`d_h=(0.684g)/(mL)`

The mass of heptane is

`m_h=31\text{ g}`

The density of water is

`d_w=(1g)/(mL)`

The mass of water is

`m_w=37\text{ g}`

The volume of heptane will be

`\begin{gathered} V_h=(m_h)/(d_h) \\ =(31)/(0.684) \\ =45.32\text{ mL} \end{gathered}`

The volume of water will be

`\begin{gathered} V_w=(m_w)/(d_w) \\ =(37)/(1) \\ =37\text{ mL} \end{gathered}`

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

`\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}`

The total volume of liquid in the cylinder will be 82.32 mL.