Question

What are the solutions to 3x^2+12x+6=0?

Answer 1

We use the quadratic formula

x =
`\frac{-b +or- \sqrt{b^(2)-4ac } }{2a}`

3x² + 12x + 6 = 0
║ ║ ║
a=3 b=12 c=6

Plug it in:

`\frac{-12 +or- \sqrt{12 ^(2) -4(3)(6)} }{2(3)}`

`(-12+or- √(144-72) )/(6)`

`(-12+or- √(72) )/(6)`

Solutions:
sol.1=
`(-12+ √(72) )/(6)`
= -0.585786
≈ -0.6

sol.2 =
`(-12- √(72) )/(6)`
= -3.41421
≈ -3.4

Answer 2

Please see the pic, I'd solved in it.