Question

Please do #1 on each. Please show your work. If you don't know DON'T ANSWER. If you need to ask me questions please use Ask for Details.

Answer 1

The answer of question #1 is 48.
To solve this, first you have to solve the (2+1) and that equals 3, now you solve 4(2+1), and that equals 12. Next, you solve the [4(2+1)+3] and that equals 15. Then, you solve {1+[4(2+1)+3} and that equals 16. Lastly, 3{1+[4(2+1)+3} equals 3 times 16=48.

3{1+[4(2+1)+3}=3[1+(4x3+3)]
=3(1+12+3)=3x16=48

Answer 2

i only know the answer for the second question.
the answer is20
11-3=8
8*5=40
40-30=10
10*2=20
the first one is 48
1+2=3
3*4=12
12+3=15
15+1=16
16*3=48