31.3k views
2 votes
Solve the system by substitution :

y=2x+2
y=3x
a.) (3,9) b.) (1,4)
c.) (-2,-4)

User Kevinpo
by
8.6k points

1 Answer

4 votes
So since we already have one of the unknowns equaling something, we start by substituting...

y= 3x so let's substitute 3x into the first equation where the y is...

y = 2x + 2
3x = 2x + 2
subtract 2x from each side
x = 2

So now we know x = 2 So we can now substitute it back into the equation but for x this time...

y = 2x + 2
y = 2(2) + 2
y = 4 + 2 = 6

So our solution set is

(2, 6)

You can check it by substituting x and y into both of the equations to see if you have a true statement...

y= 2x + 2
6 = 2×2 + 2
6 = 6

y = 3x
6 = 3×2
6 = 6

Both true so it checks!

*note- I noticed that my solution was not one of your options, but if you substitute the available option that you gave into the equations none of them work, so take a look at your possible answers and see if you didn't leave something out. ;)
User Tofu
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories