Question

A^b=cconvert between Exponential and Logarithmic form

Answer 1

`\log _a(c)=b`

Step-by-step explanation

Step 1

`a^b=c`

also, by definition:

`y=m^x\Rightarrow\log _m(y)=x`

hence; identify

`\begin{gathered} a^b=c\Rightarrow \\ so \\ y=c \\ a=m \\ b=x \end{gathered}`

now, replace

`\begin{gathered} y=m^x\Rightarrow\log _m(y)=x \\ c=a^b\Rightarrow\log _a(c)=b \end{gathered}`

therefore, the answer is

`\log _a(c)=b`

I hope this helps you