Question

ONE HUNDRED POINTS

Complete the proof.

Below is a drag and drop geometric proof. Complete the proof in your notebook.

Given: A = D

Prove: ACB ~ DCE



Choose from these possible answers:

Answer 1

Given:

`\angle \: A = \angle D`

To prove:

ACB ~ DCE

Statement:

Given,

`\bf\angle \: A = \angle D`

`\bf \angle \: BCA= \angle \: ECD`

[ vertical angles ]

`\therefore \: ACB \sim DCE`

Reason:

By AA Criterion of similarity

Answer 2

See Below.

Explanation:

We are given that ∠A = ∠D, and we want to prove that ΔACB ~ ΔDCE.

Statements: Reasons:

`1) \text{ $\angle A=\angle D$}`
`\text{Given}`

`2) \text{ }\angle BCA=\angle ECD`
`\text{Vertical Angles Are Congruent}`

`3) \text{ } \Delta ACB \sim \Delta DCE`
`\text{AA (Angle-Angle) Similarity}`