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A key code must contain 6 numerals. There are 10 numerals available. Using these numerals, how many different key codes may be created?

User Omroy
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To solve, you will raise the number of numerals available (10) to the number of numerals required for each key code (6): 10 ^ 6. This will give you the total number of possible combinations. When raising 10 to a number, you simply put as many zeros as the number of the exponent: 1,000,000
User Timfreilly
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