Question

5.0g piece of copper (specific heat = 0.385 j/g 0 C) is heat with a Bunsen burner. You know that you add 120 joules of energy to the metal. What change in temperature would you observe?

Answer 1

In this question, we have a situation in which we have to use the Calorimetry formula, which is how much heat was released or absorbed (in Joules), after we had a change in temperature of a compound. The formula for this Calorimetry question is:

Q = mcΔT

Where:

Q = is energy as Heat, 120 Joules

m = mass in grams, 5.0 grams

c = is the specific heat capacity, 0.385 J/g°C

ΔT = the change in temperature, calculated as Final Temperature - Initial T

Now we add these values into the formula:

120 = 5 * 0.385 * T

120 = 1.925T

T = 62°C of change in temperature